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C Program To Accept The String Starting With ab And Ending With abb | C Programming

C Program To Accept The String Starting With ab And Ending With abb 

#include <stdio.h>
#include <string.h>
int main(int argc, char const *argv[])
{
    char str[10];
    int len, i, q = 0;
    printf("enter the string which only contain a and b\n");
    scanf("%s", str);
    len = strlen(str);
    for (i = 0; i <= len; i++)
    {
        if (str[i] == 'a' && q == 0)
            q = 1;
        else if (str[i] == 'b' && q == 0)
            q = 6;
        else if (str[i] == 'a' && q == 1)
            q = 6;
        else if (str[i] == 'b' && q == 1)
            q = 2;
        else if (str[i] == 'a' && q == 2)
            q = 3;
        else if (str[i] == 'b' && q == 2)
            q = 2;
        else if (str[i] == 'a' && q == 3)
            q = 3;
        else if (str[i] == 'b' && q == 3)
            q = 4;
        else if (str[i] == 'a' && q == 4)
            q = 3;
        else if (str[i] == 'b' && q == 4)
            q = 5;
        else if (str[i] == 'a' && q == 5)
            q = 3;
        else if (str[i] == 'b' && q == 5)
            q = 2;
        else if (str[i] == 'a' && q == 6)
            q = 6;
        else if (str[i] == 'b' && q == 6)
            q = 6;
    }
    if (q == 5)
        printf("Given string is accepted\n");
    else
        printf("Given string is not accepted\n");
}

OUTPUT #1

C Program To Accept The String Starting With ab And Ending With abb

OUTPUT #2

C Program To Accept The String Starting With ab And Ending With abb


OUTPUT #3

C Program To Accept The String Starting With ab And Ending With abb

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