C Program To Accept The String Starting With 01 And Ending With 011 | C Programming

C Program To Accept The String Starting With 01 And Ending With 011

#include <stdio.h>

#include <string.h>

int main()

{

    char str[10];

    int len, i, q = 0;

    printf("enter the string which only contain 0 and 1\n");

    scanf("%s", str);

    len = strlen(str);

    for (i = 0; i <= len; i++)

    {

        if (str[i] == '0' && q == 0)

            q = 1;

        else if (str[i] == '1' && q == 0)

            q = 6;

        else if (str[i] == '0' && q == 1)

            q = 6;

        else if (str[i] == '1' && q == 1)

            q = 2;

        else if (str[i] == '0' && q == 2)

            q = 3;

        else if (str[i] == '1' && q == 2)

            q = 2;

        else if (str[i] == '0' && q == 3)

            q = 3;

        else if (str[i] == '1' && q == 3)

            q = 4;

        else if (str[i] == '0' && q == 4)

            q = 3;

        else if (str[i] == '1' && q == 4)

            q = 5;

        else if (str[i] == '0' && q == 5)

            q = 3;

        else if (str[i] == '1' && q == 5)

            q = 2;

        else if (str[i] == '0' && q == 6)

            q = 6;

        else if (str[i] == '1' && q == 6)

            q = 6;

    }

    if (q == 5)

        printf("Given string is accepted\n");

    else

        printf("Given string is not accepted\n");

}

Output #1

Output #2

Output #3

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